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Aaron Donald Wins 2018 NFL Defensive Player of the Year Award

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  • Aaron Donald Wins 2018 NFL Defensive Player of the Year Award

    2018 NFL Awards Roundup

    For the second consecutive season, Aaron Donald is the Defensive Player of the Year.

    In a two-man race that wasn't much of a contest, the defensive tackle who will lead the Rams into Sunday's Super Bowl against New England earned 45 votes. The only unanimous member of the 2018 All-Pro team, Donald easily outdistanced Chicago edge rusher Khalil Mack, also an All-Pro, who received five votes.

    Donald, the only Rams player selected for the top defensive honor, joins Lawrence Taylor and J.J. Watt as players to win the award in back-to-back seasons. Donald led the NFL with 20.5 sacks.
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